The amount of BaSO_4 precipitated on mixing BaCl_2(0.5 M) with H_2 SO_4(1 M) will correspond to

Correct answer: A. 0.5 M [Ba^ 2+ ]=0.5 mol L^ -1 aligned & [SO_ 4 ^ 2- ]=1 mol L^ -1 &Ba_ (a q) ^ 2+ +SO_ 4(a q) ^ 2- leftharpoons BaSO_ 4(s) aligned 0. 5 mol of Ba^ 2+ would react with 0. 5 mol of SO_4^ 2- ions to form 0.5 mol o f BaSO _ 4 .

AIIMS 2015

Exam: AIIMS
Year: 2015
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

AIIMS 2015 · Chemistry · Some Basic Concepts of Chemistry

The amount of BaSO_4 precipitated on mixing BaCl_2(0.5 M) with H_2...

The amount of

\mathrm{BaSO}_4

precipitated on mixing

\mathrm{BaCl}_2(0.5 \mathrm{M})

with

\mathrm{H}_2 \mathrm{SO}_4(1 \mathrm{M})

will correspond to

Options

A $0.5 \mathrm{M}$
B $1.0 \mathrm{M}$
C $1.5 \mathrm{M}$
D $2.0 \mathrm{M}$

Correct answer

A. $0.5 \mathrm{M}$

Step-by-step solution

\left[\mathrm{Ba}^{2+}\right]=0.5 \mathrm{ mol} \mathrm{ L}^{-1}

\begin{aligned}& {\left[\mathrm{SO}_{4}^{2-}\right]=1 \mathrm{ mol}\mathrm{ L}^{-1}} \\ &\mathrm{Ba}_{(a q)}^{2+}+\mathrm{SO}_{4(a q)}^{2-} \rightleftharpoons \mathrm{BaSO}_{4(s)} \end{aligned}

5

\mathrm{ mol}

of

\mathrm{Ba}^{2+}would react with 0.

5

\mathrm{ mol}

of

\mathrm{SO}_4^{2-} ions to form 0.5 \mathrm{ mol} o

f

\mathrm{BaSO}

_{4}

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