When 25 ~g of Na_2 SO_4 is dissolved in 10^3 ~kg of solution, its concentration will be

Correct answer: B. 25 ppm When a solute is present in very minute amounts (trace quantities), the concentration is expressed in ppm. aligned & ppm of A= mass of component A total mass of solution ×10^6 & =(0.025)/(10^3) ×10^6=25 ppm . & aligned

AIIMS 2010

Exam: AIIMS
Year: 2010
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

AIIMS 2010 · Chemistry · Some Basic Concepts of Chemistry

When 25 ~g of Na_2 SO_4 is dissolved in 10^3 ~kg of solution, its...

When

25 \mathrm{~g}

\mathrm{Na}_2 \mathrm{SO}_4

is dissolved in

10^3 \mathrm{~kg}

of solution, its concentration will be

Options

A $2.5 \mathrm{ppm}$
B $25 \mathrm{ppm}$
C $250 \mathrm{ppm}$
D $100 \mathrm{ppm}$

Correct answer

B. $25 \mathrm{ppm}$

Step-by-step solution

When a solute is present in very minute amounts (trace quantities), the concentration is expressed in ppm.

\begin{aligned}& \text{ ppm of }A=\frac{\text{ mass of component } A}{\text{ total mass of solution }} \times10^6 \\ & =\frac{0.025}{10^3} \times10^6=25 \mathrm{ppm} \text{. }\\ & \end{aligned}

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