What is the molarity of H_2 SO_4 solution that has a density of 1.84 ~g / cc at 35^ C and contains 98 \% by weight?

Correct answer: C. 18.4 M Molarity = wt. of solute mol. wt. × 1000 vol. of solution (in mL) (Volume of solution = mass density =(100)/(1.84)=54.34 mL ) Now, molarity =(98)/(98) × (1000)/(54.34)= 18.4 M

AIIMS 2009

Exam: AIIMS
Year: 2009
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

AIIMS 2009 · Chemistry · Some Basic Concepts of Chemistry

What is the molarity of H_2 SO_4 solution that has a density of...

What is the molarity of

\mathrm{H}_2 \mathrm{SO}_4

solution that has a density of

1.84 \mathrm{~g} / \mathrm{cc}

35^{\circ} \mathrm{C}

and contains

98 \%

by weight?

Options

A $4.18 \mathrm{M}$
B $8.14 \mathrm{M}$
C $18.4 \mathrm{M}$
D $18 \mathrm{M}$

Correct answer

C. $18.4 \mathrm{M}$

Step-by-step solution

Molarity

=\frac{\text{ wt. of solute }}{\text{ mol. wt. }} \times \frac{1000}{\text{ vol. of solution (in mL) }}

(Volume of solution

=\frac{\text{ mass }}{\text{ density }}=\frac{100}{1.84}=54.34 \mathrm{ mL} ) Now, molarity =\frac{98}{98}

\times

\frac{1000}{54.34}=

18.4

\mathrm{M}

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