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Black Advanced Problems in Mathematics
Exam
Black Advanced Problems in Mathematics
Subject
Mathematics
Chapter
Indefinite and Definite Integration

Black Advanced Problems in Mathematics · Mathematics · Indefinite and Definite Integration

Let f:(0, 1) arrow (0, 1) be a differentiable function such that...

Let f:(0,1)→(0,1)f:(0, 1) \rightarrow (0, 1) be a differentiable function such that f′(x)≠0f'(x) \neq 0 for all x∈(0,1)x \in (0, 1) and f(12)=32f\left(\frac{1}{2}\right) = \frac{\sqrt{3}}{2}. Suppose for all xx, lim⁡t→x∫0t1−(f(s))2ds−∫0x1−(f(s))2dsf(t)−f(x)=f(x)\lim_{t \to x} \frac{\int_0^t \sqrt{1 - (f(s))^2} ds - \int_0^x \sqrt{1 - (f(s))^2} ds}{f(t) - f(x)} = f(x). Then the value of f(14)belongsto:f \left(\frac{1}{4}\right)belongs to :

Options

  1. A\left\{ \frac{\sqrt{7}}{4}, \frac{\sqrt{15}}{4} \right\}
  2. B\left\{ \frac{\sqrt{7}}{3}, \frac{\sqrt{15}}{3} \right\}
  3. C\left\{ \frac{\sqrt{7}}{2}, \frac{\sqrt{15}}{2} \right\}
  4. D\left\{ \sqrt{7}, \sqrt{15} \right\}

Correct answer

A. \left\{ \frac{\sqrt{7}}{4}, \frac{\sqrt{15}}{4} \right\}

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