Question
XmL of H _ 2 gas effuses through a hole in a container in 5 seconds. The time taken for the effusion of the same volume of the gas specified below under identical conditions is :
BITSAT
Chemistry
Chemical Kinetics
2021
BITSAT 2021
BITSAT Chemistry Question (2021) — Solution
Options
- A. 10 seconds : He
- B. 20 seconds: O _ 2
- C. 25 seconds: CO
- D. 55 seconds : CO _ 2
Answer
B. 20 seconds: O _ 2
Step-by-step solution
Under identical conditions, r_ 1 r_ 2 = M _ 2 M _ 1 As rate of diffusion is also inversely proportional to time, we will have, t_ 2 t_ 1 = M _ 2 M _ 1 (A) Thus, For He , t_ 2 = 4 2 (5 s)=5 2 s 10 s; (B) For O _ 2 , t_ 2 = 32 2 (5 s)=20 s (C) For CO , t_ 2 = 28 2 (5 s) 25 s; (D) For CO _ 2 , t_ 2 = 44 2 (5 s) 55 s #
Related: Chemistry — Chemical Kinetics · All PYQ Banks