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BITSAT Chemistry Chemical Kinetics 2024 BITSAT 2024 (Memory Based Paper 2)

BITSAT Chemistry Question (2024) — Solution

Question

Calculate the activation energy of a reaction, whose rate constant doubles on raising the temperature from 300 K to 600 K .

Options

  1. A. 3.45 ~kJ / mol
  2. B. 6.90 ~kJ / mol
  3. C. 9.68 ~kJ / mol
  4. D. 19.6 ~kJ / mol

Answer

A. 3.45 ~kJ / mol

Step-by-step solution

( k_2 k_1 )= E_a 2.303 R [ 1 T_1 - 1 T_2 ] or, ( 2 k k )= E_a 2.303 8.3 [600-300] 300 600 E_a 3.45 ~kJ / mol

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