BITSAT Chemistry Question (2024) — Solution

Step-by-step solution

The reaction involved is, NaCl + H _2 O Electrolysis 1 2 H _2+ Cl _2+ NaOH Amount of NaCl present in 0.5 L of 1.0 M , NaCl =0.5 mol Quantity of electricity passed =965 5 coulombs. 4825 coulombs will decompose NaCl . aligned & = 4825 96500 ~mol \\ & =0.05 ~mol aligned NaOH formed in the solution will also be 0.05 mol . Volume of solution =0.5 ~L Molarity of NaOH in the solution aligned & = 0.05 moles 0.5 ~L =0.1 M \\ & =10^ -1 M aligned array rlrl & & pOH & =1 \\ or & pH & =14-1=13 array