Question
0.20 ~g of an organic compound gave 0.12 ~g of AgBr By using Carius method, the percentage of bromine in the compound will be
0.20 ~g of an organic compound gave 0.12 ~g of AgBr By using Carius method, the percentage of bromine in the compound will be
D. 25 \%
Given, Mass of an organic compound =0.20 ~g Mass of AgBr =0.12 ~g Molecular mass of AgBr =188 ~g ~mol ^ -1 188 ~g of AgBr contains 80 ~g of bromine 0.12 ~g of AgBr will contain = 80 188 0.12 =0.05 ~g of bromine Percentage of bromine = 0.05 0.20 100 =25 \%
Related: Chemistry — General Organic Chemistry · All PYQ Banks