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BITSAT Chemistry Solutions 2024 BITSAT 2024 (Memory Based Paper 3)

BITSAT Chemistry Question (2024) — Solution

Question

58.5 g of NaCl and 180 g of glucose were separately dissolved in 1000 mL of water. Identify the correct statement regarding the elevation of boiling point of the resulting solution.

Options

  1. A. NaCl solution will show higher elevation of boiling point.
  2. B. Glucose solution will show higher elevation of boiling point.
  3. C. Both the solution will show equal elevation of boiling point.
  4. D. None will show boiling point elevation.

Answer

A. NaCl solution will show higher elevation of boiling point.

Step-by-step solution

aligned 58.5 ~g NaCl & = 58.5 58.5 ~mol \\ & =1 ~mol \\ 180 ~g of glucose & = 180 180 =1 ~mol aligned Thus, we have 1 M NaCl and 1 M glucose solution. But NaCl dissociates in the solution and glucose does not dissociates. Thus particle concentration is more in NaCl . Hence, NaCl solution will have higher elevation in boiling point.

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