BITSAT
Chemistry
Some Basic Concepts of Chemistry
2020
BITSAT 2020
BITSAT Chemistry Question (2020) — Solution
Question
An ideal gaseous mixture of ethane ( C _ 2 H _ 6 ) and ethene ( C _ 2 H _ 4 ) occupies 28 litre at 1 atm and 273 ~K . The mixture reacts completely with 128 ~g O _ 2 to produce CO _ 2 and H _ 2 O . Mole fraction at C _ 2 H _ 6 in the mixture is:
Options
- A. 0.6
- B. 0.4
- C. 0.5
- D. 0.8
Step-by-step solution
C _ 2 H _ 6 +3.5 O _ 2 2 CO _ 2 +3 H _ 2 O ; C _ 2 H _ 4 +3 O _ 2 2 CO _ 2 +2 H _ 2 O Let volume of ethane is x litre, 22.4 4=3.5 x +3(28- x ) x =11.2 litre at constant T and P , V n ; Mole fraction of C _ 2 H _ 6 in mixture = 11.2 28 =0.4
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