Question
Standard entropy of X_2, Y_2 and X Y_2 are 60,40 and 50 JK ^ -1 ~mol ^ -1 , respectively. For the reaction, 1 2 X_2+ 3 2 Y_2 X Y_3, H=-30 ~kJ , to be at equilibrium, the temperature will be
BITSAT
Chemistry
Thermodynamics (C)
2022
BITSAT 2022
BITSAT Chemistry Question (2022) — Solution
Options
- A. 1250 ~K
- B. 500 ~K
- C. 750 ~K
- D. 1000 ~K
Answer
C. 750 ~K
Step-by-step solution
S=S (X Y_3 )- 1 2 S (X_2 )- 3 2 S (Y_2 ) =50-30-60=-40 ~J ~mol ^ -1 ~K ^ -1 H=-30 ~kJ =-3000 ~J G= H-T S At equilibrium, G=0 T= H S = -3000 -40 =750 ~K
Related: Chemistry — Thermodynamics (C) · All PYQ Banks