The combustion of benzene (L) gives CO _2( ~g ) and H _2 O (L). Given that heat of combustion of benzene at constant volume is -3263.9 ~kJ ~mol ^ - ^1 at 25^ C ; heat of combustion (in kJ mol ^ -1 ) of benzene at constant pressure will be : (R=8.314 JK ^ -1 ~mol ^ -1 )

Question

Quantrex Academy · Accepted Answer

Correct answer: D. -3267.6

C _6 H _6( I )+ 15 2 O _2( ~g ) 6 CO _2( ~g )+3 H _2 O ( l ) n_g=6- 15 2 =- 3 2 H= U+ n_ g R T =-3263.9+ (- 3 2 ) 8.314 10^ -3 298 =-3263.9+(-3.71)=-3267.6 ~kJ ~mol ^ -1

BITSAT Chemistry Question (2024) — Solution

Question

Options

Answer

Step-by-step solution