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BITSAT Mathematics Application of Derivatives 2020 BITSAT 2020

BITSAT Mathematics Question (2020) — Solution

Question

Consider the function f(x)=|x-1| /x^ 2 , then f(x) is

Options

  1. A. increasing in (0,1) (2, )
  2. B. increasing in (- , 0) (1,2)
  3. C. decreasing in (0,1) (2, )
  4. D. decreasing in (0,1) (2, )

Answer

D. decreasing in (0,1) (2, )

Step-by-step solution

f(x)= |x-1| x^ 2 = \ array l 1-x x^ 2 , x 1 array . Clearly, f(x) is continuous for all x R except at x=0 f^ (x)= \ array l x-2 x^ 3 , x 1 array . f^ (x)>0 x 2 Hence, f(x) is increasing in (- , 0) (1,2) and decreasing in (0,1) (2, ).

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