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BITSAT Mathematics Application of Derivatives 2020 BITSAT 2020

BITSAT Mathematics Question (2020) — Solution

Question

Let x+y=3- 4 and x-y=4 2 then the greatest of x y is

Options

  1. A. 3 4
  2. B. 1
  3. C. 1 2
  4. D. 2

Answer

B. 1

Step-by-step solution

x= 3- 4 +4 2 2 = 3- (1- ^ 2 2 )+4 2 2 =(1+ 2 )^ 2 y= 3- 4 -4 2 2 = 3- (1- ^ 2 2 )+4 2 2 =(1- 2 )^ 2 x y= (1- ^ 2 2 )^ 2 = ^ 4 2 1

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