Question
f(x)= ( e^ 2 x -1 e^ 2 x +1 ) is
BITSAT
Mathematics
Application of Derivatives
2021
BITSAT 2021
BITSAT Mathematics Question (2021) — Solution
Options
- A. an increasing function
- B. a decreasing function
- C. an even function
- D. None of these
Answer
A. an increasing function
Step-by-step solution
array l f (x)= ( e^ 2 x -1 e^ 2 x +1 ) \\ f (-x)= e^ -2 x -1 e^ -2 x +1 = 1-e^ 2 x 1+e^ 2 x \\ f (-x)= - (e^ 2 x -1 ) e^ 2 x +1 =- f (x) array f (x) is an odd function. Again, f ^ (x)= 4 e^ 2 x (1+e^ 2 x )^ 2 >0, x R f (x) is an increasing function.
Related: Mathematics — Application of Derivatives · All PYQ Banks