Question
The curve given by x+y=e^ x y has a tangent parallel to the Y-axis at the point
BITSAT
Mathematics
Application of Derivatives
2023
BITSAT 2023 (Memory Based Paper 1)
BITSAT Mathematics Question (2023) — Solution
Options
- A. (0,1)
- B. (1,0)
- C. (1,1)
- D. None of these
Answer
B. (1,0)
Step-by-step solution
x+y=e^ x y Differentiating w.r.t. x, we get 1+ d y d x =e^ x y [y+x d y d x ] d y d x (1-x e^ x y )=y e^ x y -1 d y d x = y e^ x y -1 1-x e^ x y d y d x = , as tangent is parallel to Y -axis 1-x e^ x y =0 xe ^ xy =1 This holds, when x=1 and y=0
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