If the angle made by the tangent at the point (x_0, y_0 ) on the curve x=12(t+ t t), y=12 (1+ t)^2, 0 t 2 , with the positive x -axis is 3 , then y_0 is equal to

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Correct answer: C. 27

Given equation of curve x=12(t+ t t), y=12(1+ t)^2 Differentiate w.r.t ' t ', aligned & d x d t =12 (1+ ^2 t- ^2 t ) \ & d x d t =12(1+ 2 t) and d y d t \ & =24(1+ t) t \ & d y d x = 2(1+ t) t 1+ 2 t aligned

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