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BITSAT Mathematics Area Under Curves 2020 BITSAT 2020

BITSAT Mathematics Question (2020) — Solution

Question

The line y=m x bisects the area enclosed by lines x =0, y =0 and x =3 / 2 and the curve y =1+4 x - x ^ 2 Then the value of m is

Options

  1. A. 13 6
  2. B. 13 2
  3. C. 13 5
  4. D. 13 7

Answer

A. 13 6

Step-by-step solution

y=1+4 x-x^ 2 =5-(x-2)^ 2 We have _ 0 ^ 3 / 2 (1+4 x-x^ 2 ) dx =2 _ 0 ^ 3 / 2 mx dx = 3 2 +2 ( 9 4 )- 1 3 ( 27 8 )= m 9 4 On solving we get m = 13 6

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