Question
If a chord of the circle x^ 2 +y^ 2 =8 makes equal intercets of length a on the coordinate axes, then
BITSAT
Mathematics
Circle
2020
BITSAT 2020
BITSAT Mathematics Question (2020) — Solution
Options
- A. | a |<8
- B. | a |<4 2
- C. | a |<4
- D. | a |>4
Answer
C. | a |<4
Step-by-step solution
Since the chord makes equal intercepts of length a on the coordinate axes. So, its equation can be written as x y = a . This line meets the given circle at two distinct points. So, length of the perpendicular from the centre (0,0) of the given circle must be less than the radius. i.e. | a 2 |< 8 a ^ 2 <16 | a |<4
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