Question
If the coordinates at one end of a diameter of the circle x^ 2 +y^ 2 -8 x-4 y+c=0 are (-3,2) , then the coordinates at the other end are
BITSAT
Mathematics
Circle
2020
BITSAT 2020
BITSAT Mathematics Question (2020) — Solution
Options
- A. (5,3)
- B. (6,2)
- C. (1,-8)
- D. (11,2)
Answer
D. (11,2)
Step-by-step solution
The centre of the given circle is C (4,2) Let A (-3,2) If ( , ) are the coordinates of the other end of the diameter, then, as the middle ploint of the diameter is the centre, -3 2 =4 and +2 2 =2 =11, =2 Thus, the coordinates of the other end of diameter are (11,2)
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