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BITSAT Mathematics Circle 2023 BITSAT 2023 (Memory Based Paper 2)

BITSAT Mathematics Question (2023) — Solution

Question

The equation of the circle with centre (0,2) and radius 2 is x^2+y^2-m y=0. The value of m is

Options

  1. A. 1
  2. B. 2
  3. C. 4
  4. D. 3

Answer

C. 4

Step-by-step solution

Here h=0, k=2 and r=2. Therefore, the required equation of the circle is : (x-0)^2+(y-2)^2=(2)^2 or x^2+y^2-4 y+4=4 or x^2+y^2-4 y=0

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