Question
The locus of the mid-point of a chord of the circle x^2+y^2=4, which subtends a right angle at the origin is
BITSAT
Mathematics
Circle
2024
BITSAT 2024 (Memory Based Paper 3)
BITSAT Mathematics Question (2024) — Solution
Options
- A. x+y=2
- B. x^2+y^2=1
- C. x^2+y^2=2
- D. x+y=1
Answer
C. x^2+y^2=2
Step-by-step solution
According to question, O C= h^2+k^2 In O C B, aligned & 45^ = h^2+k^2 2 \\ & h^2+k^2 2 = 1 2 \\ & h^2+k^2=2 aligned Replacing h x and k y Locus x^2+y^2=2
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