Question
The modulus of the complex number z such that |z+3-i|=1 and (z)= is equal to
BITSAT
Mathematics
Complex Number
2024
BITSAT 2024 (Memory Based Paper 3)
BITSAT Mathematics Question (2024) — Solution
Options
- A. 3
- B. 2
- C. 9
- D. 4
Answer
A. 3
Step-by-step solution
Let z=x+i y Given, |z+3-i|=1 aligned & |(x+3)+(y-1) i|=1 \\ & (x+3)^2+(y-1)^2 =1 \\ & (x+3)^2+(y-1)^2=1 (i) aligned Above is the equation of circle with centre (-3,1) and radius =1 Also, (z)= ^ -1 | y x |= | y x |= =0 y=0 By Eq. (i), aligned & x & =-3 \\ & z & =-3+0 i \\ & Modulus of z & =3 aligned
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