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BITSAT Mathematics Definite Integration 2020 BITSAT 2020

BITSAT Mathematics Question (2020) — Solution

Question

_ 0 ^ dx ( x ^ 2 + a ^ 2 ) ( x ^ 2 + b ^ 2 ) is

Options

  1. A. a b a+b
  2. B. 2(a+b)
  3. C. 2 a b(a+b)
  4. D. (a+b) 2 a b

Answer

C. 2 a b(a+b)

Step-by-step solution

_ 0 ^ d x (x^ 2 +a^ 2 ) (x^ 2 +b^ 2 ) = 1 b^ 2 -a^ 2 _ 0 ^ (x^ 2 +b^ 2 )- (x^ 2 +a^ 2 ) (x^ 2 +a^ 2 ) (x^ 2 +b^ 2 ) = 1 b^ 2 -a^ 2 _ 0 ^ [ 1 x^ 2 +a^ 2 - 1 x^ 2 +b^ 2 ] d x = 1 b^ 2 -a^ 2 [ 1 a ^ -1 x a - 1 b ^ -1 x b ]_ 0 ^ = 1 b^ 2 -a^ 2 [ 2 a - 2 b ]= 2 a b(a+b)

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