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BITSAT Mathematics Determinants 2022 BITSAT 2022

BITSAT Mathematics Question (2022) — Solution

Question

Given 2 x-y+2 z=2, x-2 y+z=-4, x+y+ z=4, then the value of such that the given system of equation has no solution is

Options

  1. A. -3
  2. B. 1
  3. C. 0
  4. D. 3

Answer

D. 3

Step-by-step solution

Since, the system has no solution. | array ccc 2 & -1 & 2 \\ 1 & -2 & -1 \\ 1 & 1 & array |=0 2(-2 +1)+1( +1)+2(3)=0 -4 +2+ +1+6=0 3 =9 =3

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