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BITSAT Mathematics Determinants 2024 BITSAT 2024 (Memory Based Paper 3)

BITSAT Mathematics Question (2024) — Solution

Question

Suppose p, q, r 0 and system of equation gathered (p+a) x+b y+c z=0 \\ a x+(q+b) y+c z=0 gathered a x+b y+(r+c) z=0, has a non-trivial solution, then the value of a p + b q + c r is

Options

  1. A. -1
  2. B. 0
  3. C. 1
  4. D. 2

Answer

A. -1

Step-by-step solution

Let |A|= | array ccc p+a & b & c \\ a & q+b & c \\ a & b & r+c array | Also, given that equations has non trivial solution |A|=0 aligned & | array ccc p+a & b & c \\ a & q+b & c \\ a & b & r+c array |=0 \\ & (p+a)[(q+b)(r+c)-b c]-b[a(r+c)-c a] \\ & +c[a b-a(q+b)]=0 \\ & (p+a)[q r+q c+b r]-b[a r]+c[-a q]=0 \\ & p q r+p q c+p b r+a q r=0 aligned Dividing whole equation by p q r aligned & p q r p q r + p q c p q r + p r b p q r + q r a p q r & =0 \\ & 1+ c r + b q + a p & =0 \\ & a p + b q + c r & =-1 aligned

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