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BITSAT Mathematics Determinants 2024 BITSAT 2024 (Memory Based Paper 2)

BITSAT Mathematics Question (2024) — Solution

Question

The equations x-y+2 z=4 3 x+y+4 z=6 x+y+z=1 have

Options

  1. A. unique solution
  2. B. infinitely many solutions
  3. C. no solution
  4. D. two solutions

Answer

B. infinitely many solutions

Step-by-step solution

Given equations, x-y+2 z=4 3 x+y+4 z=6 x+y+z=1 Let = | array ccc 1 & -1 & 2 \\ 3 & 1 & 4 \\ 1 & 1 & 1 array | =1(1-4)+1(3-4)+2(3-1) =-3-1+4=0 and _1= | array ccc 4 & -1 & 2 \\ 6 & 1 & 4 \\ 1 & 1 & 1 array | =4(1-4)+1(6-4)+2(6-1) =-12+2+10=0 Now, =0 and _1=0 These equations have infinitely many solutions.

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