Question
The solutions of (x+y+1) d y=d x are
BITSAT
Mathematics
Differential Equations
2020
BITSAT 2020
BITSAT Mathematics Question (2020) — Solution
Options
- A. x+y+2=C e^ y
- B. x+y+4=C y
- C. (x+y+2)=C y
- D. (x+y+2)=C-y
Answer
A. x+y+2=C e^ y
Step-by-step solution
Putting x+y+1=u, we have d u=d x+d y and the given equation reduces to u(d u-d x)= d x u d u u+1 =d x u- (u+1)=x (x+y+2)=y+ constant x+y+2=C e^ y
Related: Mathematics — Differential Equations · All PYQ Banks