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BITSAT Mathematics Differential Equations 2021 BITSAT 2021

BITSAT Mathematics Question (2021) — Solution

Question

If the slope of the tangent to the curve at any point P (x, y) is y x - ^ 2 y x , then the equation of a curve passing through (1, 4 ) is

Options

  1. A. ( y x )+ x=1
  2. B. ( y x )+ y=1
  3. C. ( x y )+ x=1
  4. D. ( x y )+ y=1

Answer

A. ( y x )+ x=1

Step-by-step solution

According to the condition, dy dx = y x - ^ 2 y x (i) This is a homogeneous differential equation Substituting y=v x, we get array l v+x dv dx =v- ^ 2 v \\ x dv dx =- ^ 2 v \\ ^ 2 vdv =- dx x \\ v=- x+ C \\ y x + x= C array Substituting x =1, y= 4 , we get C =1 Thus, we get ( y x )+ x=1 which is the required solution.

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