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BITSAT Mathematics Differential Equations 2023 BITSAT 2023 (Memory Based Paper 1)

BITSAT Mathematics Question (2023) — Solution

Question

The number of solutions of d y d x = y+1 x-1 , when y(1)=2 is

Options

  1. A. none
  2. B. one
  3. C. two
  4. D. infinite

Answer

B. one

Step-by-step solution

Since, d y d x = y+1 x-1 d y y+1 = d x x-1 After integrating on both sides, we have (y+1)= (x-1)- C C(y+1)=(x-1) C= x-1 y+1 If x=1, then y=2, so C=0 Therefore, x-1=0 Hence, there is only one solution.

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