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BITSAT Mathematics Differentiation 2021 BITSAT 2021

BITSAT Mathematics Question (2021) — Solution

Question

If x= 1-t^ 2 1+t^ 2 and y= 2 t 1+t^ 2 , then d y d x is equal to :

Options

  1. A. - y x
  2. B. y x
  3. C. - x y
  4. D. x y

Answer

C. - x y

Step-by-step solution

Let x= 1-t^ 2 1+t^ 2 and y= 2 t 1+t^ 2 Put t= , we get x= 1- ^ 2 1+ ^ 2 and y= 2 1+ ^ 2 x= 2 and y= 2 dx d =-2 2 and dy d =2 2 Now, dy dx = dy d d dx =- 2 2 =- x y

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