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BITSAT Mathematics Differentiation 2023 BITSAT 2023 (Memory Based Paper 1)

BITSAT Mathematics Question (2023) — Solution

Question

If y= ( 1+ 2 1- 2 ) , then d y d at = 3 4 is :

Options

  1. A. -2
  2. B. 2
  3. C. 2
  4. D. None of these

Answer

A. -2

Step-by-step solution

y= 1+ 2 1- 2 y= 2 ^2 2 ^2 = ^2 y= Differentiate w.r.t. ' ', we get: d y d =- cosec ^2 Now, ( dy d )_ = 3 4 =- cosec ^2 ( 3 4 ) =- cosec ^2 ( - 4 )=- cosec ^2 4 =-2

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