Quantrex Academy · Free BITSAT PYQ solutions
BITSAT Mathematics Differentiation 2024 BITSAT 2024 (Memory Based Paper 2)

BITSAT Mathematics Question (2024) — Solution

Question

At x= ^2 4 , d d x ( ^ -1 ( x )+ ^ -1 (e^x ) )=

Options

  1. A. 1 e ^ ^2 2 -1 - 1
  2. B. 4 + 1 e ^ ^2 + e ^ ^2 / 2
  3. C. 1 e ^ ^2 + e ^ ^2 / 2 + 2 ( 2 )
  4. D. 1 e ^ + 1

Answer

A. 1 e ^ ^2 2 -1 - 1

Step-by-step solution

d d x ( ^ -1 ( x )+ ^ -1 ( e ^x ) ) = (- x ) 1+ ^2 x ( 1 2 x )+ 1 e^x e^ 2 x -1 e^x but when x= ^2 4 =- - 2 1+ ^2 2 ( 1 2 ) ( 2 )+ 1 e^ ^2 / 2 -1 =- 1 + 1 e^ ^2 / 2 -1

Practice more on Quantrex App →

Related: Mathematics — Differentiation · All PYQ Banks