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BITSAT Mathematics Ellipse 2020 BITSAT 2020

BITSAT Mathematics Question (2020) — Solution

Question

If x ma + y nb =1 touches the ellipse x^ 2 a^ 2 + y^ 2 b^ 2 =1, then

Options

  1. A. m ^ 2 = n ^ 2 n ^ 2 -1 or n ^ 2 = m ^ 2 ~m ^ 2 -1
  2. B. m ^ 2 = n ^ 2 n ^ 2 +1 or n ^ 2 = m ^ 2 ~m ^ 2 +1
  3. C. m ^ 2 = n ^ 2 +1 n ^ 2 or n ^ 2 = m ^ 2 +1 ~m ^ 2
  4. D. m ^ 2 = n ^ 2 -1 n ^ 2 or n ^ 2 = m ^ 2 -1 ~m ^ 2

Answer

A. m ^ 2 = n ^ 2 n ^ 2 -1 or n ^ 2 = m ^ 2 ~m ^ 2 -1

Step-by-step solution

The line is y=- nb ma x-n b. It will touch the ellipse if (-n b)^ 2 =a^ 2 (- n b m a )^ 2 +b^ 2 [ c ^ 2 = a ^ 2 ~m ^ 2 + b ^ 2 ] n^ 2 = n^ 2 m^ 2 +1 m ^ 2 = n ^ 2 n ^ 2 -1 or n ^ 2 = m ^ 2 ~m ^ 2 -1

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