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BITSAT Mathematics Functions 2020 BITSAT 2020

BITSAT Mathematics Question (2020) — Solution

Question

The domain of the function f(x)= x- 1-x^ 2 is

Options

  1. A. [-1,- 1 2 ] [ 1 2 , 1 ]
  2. B. [-1,1]
  3. C. (- ,- 1 2 ] [ 1 2 ,+ )
  4. D. [ 1 2 , 1 ]

Answer

D. [ 1 2 , 1 ]

Step-by-step solution

For f(x) to be defined, we must have x- 1-x^ 2 0 or x 1-x^ 2 >0 x^ 2 1-x^ 2 or x^ 2 1 2 Also, 1-x^ 2 0 or x^ 2 1. Now, x^ 2 1 2 (x- 1 2 ) (x+ 1 2 ) 0 x - 1 2 or x 1 2 Also, x^ 2 1 (x-1)(x+1) 0 -1 x 1 Thus, x>0, x^ 2 1 2 and x^ 2 1 x [ 1 2 , 1 ]

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