BITSAT Mathematics Question (2024) — Solution

Step-by-step solution

Given function f(x)= 2 x^2-7 x+5 3 x^2-5 x-2 Here, f ( x ) should be greater than or equal to 0 . So, 2 x^2-7 x+5=0 2 x^2-5 x-2 x+5=0 (x-1)(2 x-5)=0 x=1, 5 2 3 x^2-5 x-2=0 3 x^2-6 x+x-2=0 3 x(x-2)+1(x-2)=0 (x-2)(3 x+1)=0 x=2, -1 3 When we include x= -1 3 , 2 then f(x) would give not define value so, we will exclude these values from the domain. When we take values between (- 1 3 , 1 ) and So, domain is (- , -1 3 ) [1,2) [ 5 2 , )