A B C is a triangular park with A B=A C=100 ~m . A TV tower stands at the mid-point of B C. The angles of elevation of the top of the tower at A, B, C are 45^ , 60^ , 60^ respectively. The height of the tower is

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Correct answer: B. 50 3 ~m

According to question, Let D E=h and C D=D B=x In E B D, 60^ = h x x= h 3 Now, in A D E aligned & 45^ = E D D A \ & D A=h aligned In A B D, by applying Pythagoras theorem aligned & ( h 3 )^2+h^2=100^2 \ & 4 h^2 3 =10000 h=50 3 aligned

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