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BITSAT Mathematics Indefinite Integration 2021 BITSAT 2021

BITSAT Mathematics Question (2021) — Solution

Question

The value of ( x) d x is :

Options

  1. A. 1 2 [ ( x)+ ( x)]+C
  2. B. x 2 [ ( x)+ ( x)]+C
  3. C. x 2 [ ( x)- ( x)]+C
  4. D. 1 2 [ ( x)- ( x)]+C

Answer

B. x 2 [ ( x)+ ( x)]+C

Step-by-step solution

Let \( I = ( x ) 1 ~d x . . (i) \) Use integral by parts, \( aligned &I= ( x) x- [- ( x)] 1 x x d x \\ &=x ( x)+ ( x) 1 d x \\ &=x ( x)+ [ ( x) x- ( x) 1 x x d x ]+C \\ &=x ( x)+ [x ( x)- ( x) d x ]+C \\ &=x\ ( x)+ ( x)\ -I+C[f r o m Eq. (i) ] \\ & I= x 2 \ ( x)+ ( x)\ +C aligned \)

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