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BITSAT Mathematics Indefinite Integration 2024 BITSAT 2024 (Memory Based Paper 1)

BITSAT Mathematics Question (2024) — Solution

Question

The value of e^ ( - ) d is

Options

  1. A. e^ +c
  2. B. e^ +c
  3. C. e^ ( + )+c
  4. D. e^ +c

Answer

D. e^ +c

Step-by-step solution

Let I= e^ ( - ) d Put =t ^2 d =d t d = d t 1+t^2 I= e^t ( 1+t^2 - t 1+t^2 ) d t 1+t^2 = e^t ( 1 1+t^2 - t (1+t^2 )^ 3 / 2 ) d t Integrating first part by parts we have, = 1 1+t^2 e^t+ t (1+t^2 )^ 3 / 2 e^t d t - t (1+t^2 )^ 3 / 2 e^t d t+c = e^t 1+t^2 +c=e^ +c

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