Question
The maximum value of z=6 x+8 y subject to constraints 2 x+y 30, x+2 y 24 and x 0, y 0 is
BITSAT
Mathematics
Linear Programming
2020
BITSAT 2020
BITSAT Mathematics Question (2020) — Solution
Options
- A. 90
- B. 120
- C. 96
- D. 240
Answer
B. 120
Step-by-step solution
Here, 2 x+y 30, x+2 y 24, x, y 0 The shaded region represents the feasible region, hence z =6 x +8 y . Obviously it is maximum at (12,6) Hence z=12 6+8 6=120
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