Question
The number of possible outcomes in a throw of n ordinary dice in which at least one of the dice shows an odd number is
BITSAT
Mathematics
Permutation Combination
2020
BITSAT 2020
BITSAT Mathematics Question (2020) — Solution
Options
- A. 6^ n -1
- B. 3^ n -1
- C. 6^ n -3^ n
- D. None of these
Answer
C. 6^ n -3^ n
Step-by-step solution
Total number of ways =6 6 to n times =6^ n Total number of ways to show only even number =3 3 to n times =3^ n required number of ways =6^ n -3^ n
Related: Mathematics — Permutation Combination · All PYQ Banks