Question
How many different nine digit numbers can be formed from the number 223355888 by rearranging its digits so that the odd digits occupy even positions?
BITSAT
Mathematics
Permutation Combination
2023
BITSAT 2023 (Memory Based Paper 2)
BITSAT Mathematics Question (2023) — Solution
Options
- A. 16
- B. 36
- C. 60
- D. 180
Answer
C. 60
Step-by-step solution
X - X - X - X - X . The four digits 3, 3, 5,5 can be arranged at (-) places in 4 ! 2 ! 2 ! =6 ways. The five digits 2,2,8,8,8 can be arranged at (X) places in 5 ! 2 ! 3 ! ways =10 ways Total no. of arrangements =6 10=60 ways
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