Question
A person invites a party of 10 friends at dinner and place so that 4 are on one round table and 6 on the other round table. Total number of ways in which he can arrange the guests is
BITSAT
Mathematics
Permutation Combination
2024
BITSAT 2024 (Memory Based Paper 3)
BITSAT Mathematics Question (2024) — Solution
Options
- A. 10! 6!
- B. 10! 24
- C. 9! 24
- D. None of these
Answer
B. 10! 24
Step-by-step solution
Total person =10 Two groups are formed containing 4 and 6 persons. Total ways of formation of groups = 10! 4!6! Now, 4 persons can be arranged on round table =(4-1)!=3! and 6 persons can be arranged on round table =(6-1) ! =5! Total ways of arranging the guest = 10! 4!6! 3! 5!= 10! 24
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