How many different nine digit numbers can be formed from the number 223355888 by rearranging its digits so that the odd digits occupy even positions

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Correct answer: C. 60

Here we have 4 odd digits (3,3,5,5) and 5 even digits (2, 2, 8, 8, 8). O E O E O O E O where, E even place and O odd place Number of ways odd digits will be place on even places = 4! 2!2! Number of ways even digits will be place on odd places aligned & = 5! 2!3! \ & Total number of ways = 4! 2!2! 5! 2!3! =60 aligned

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