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BITSAT Mathematics Probability 2023 BITSAT 2023 (Memory Based Paper 2)

BITSAT Mathematics Question (2023) — Solution

Question

If E and F are events such that 0 < P ( F ) < 1, then

Options

  1. A. P(E F)+P( E F)=1
  2. B. P(E F)+P(E F )=1
  3. C. P( E F)+P(E F )=1
  4. D. P(E F )+P( E F )=0

Answer

A. P(E F)+P( E F)=1

Step-by-step solution

P(E F)+P( E F) = P(E F)+P( E F) P(F) = P((E E ) F) P(F) = P(F) P(F) =1

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