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BITSAT Mathematics Probability 2023 BITSAT 2023 (Memory Based Paper 1)

BITSAT Mathematics Question (2023) — Solution

Question

The probability of getting sum more than 7 when a pair of dice are thrown is:

Options

  1. A. 7 36
  2. B. 5 12
  3. C. 7 12
  4. D. None of these

Answer

B. 5 12

Step-by-step solution

Here n(S)=6^2=36 Let E be the event "getting sum more than 7" i.e. sum of pair of dice =8,9,10,11,12 i.e. E= \ array lllll (2,6) & (3,5) & (4,4) & (5,3) & (6,2) \\ (3,6) & (4,5) & (5,4) & (6,3) \\ (4,6) & (5,5) & (6,4) & \\ (5,6) & (6,5) & (6,6) & array \ n(E)=15 . Req. prob = n(E) n(S) = 15 36 = 5 12

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