Question
The probability of getting 10 in a single throw of three fair dice is
BITSAT
Mathematics
Probability
2024
BITSAT 2024 (Memory Based Paper 3)
BITSAT Mathematics Question (2024) — Solution
Options
- A. 1 6
- B. 1 8
- C. 1 9
- D. 1 5
Answer
B. 1 8
Step-by-step solution
Total outcomes =216 Now, number of cases of getting 10 from 3 dices in single throw are Case 1:~1+3+6 outcomes =3!=6 Case 2:~1+4+5 outcomes =3 ! =6 Case 3:~2+2+6 outcomes = 3! 2! =3 Case 4:~2+3+5 outcomes =3!=6 Case 5:~2+4+4 outcomes = 3! 2! =3 Case 6:~3+3+4 outcomes = 3! 2! =3 Favourable outcomes =27 Probability = 27 216 = 1 8 aligned & & (x+24)(x-20) & =0 \\ & & x & =20 aligned
Related: Mathematics — Probability · All PYQ Banks