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BITSAT Mathematics Quadratic Equation 2021 BITSAT 2021

BITSAT Mathematics Question (2021) — Solution

Question

Find the value of a such that the sum of the squares of the roots of the equation x^ 2 -(a-2) x-(a+1)=0 is least.

Options

  1. A. 4
  2. B. 2
  3. C. 1
  4. D. 3

Answer

C. 1

Step-by-step solution

Let , be the roots of the equation. + =a-2 and =-(a+1) Now, ^ 2 + ^ 2 =( + )^ 2 -2 =(a-2)^ 2 +2(a+1)=(a-1)^ 2 +5 ^ 2 + ^ 2 will be minimum if (a-1)^ 2 =0, i.e. a=1.

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