Question
In a statistical investigation of 1003 families of Calcutta, it was found that 63 families has neither a radio nor a TV, 794 families has a radio and 187 has TV. The number of families in that group having both a radio and a TV is
BITSAT
Mathematics
Sets and Relations
2024
BITSAT 2024 (Memory Based Paper 3)
BITSAT Mathematics Question (2024) — Solution
Options
- A. 36
- B. 41
- C. 32
- D. None of these
Answer
B. 41
Step-by-step solution
aligned Given, n(R) & =794 \\ n(T) & =187 \\ n(R T)^ & =63 \\ n( Total ) & =n(R T)+n(R T)^ \\ 1003 & =n(R T)+63 \\ n(R T) & =940 aligned By set theory array lc & n(R T)=n(R)+n(T)-n(R T) \\ & 940=794+187-n(R T) \\ & n(R T)=981-940=41 array
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