Question
In an examination, 62 \% of the candidates failed in English, 42% in Mathematics and 20% in both. The number of those who passed in both the subjects is
BITSAT
Mathematics
Sets and Relations
2024
BITSAT 2024 (Memory Based Paper 1)
BITSAT Mathematics Question (2024) — Solution
Options
- A. 11
- B. 16
- C. 18
- D. None of these
Answer
B. 16
Step-by-step solution
From the given condition, a + c =62 k ; b + c =42 k and c =20 k Hence a =42 k and b =22 k Number of students who failed in none means passed in both = n =100 k -( a + b + c ) =100 k -(42 k +22 k +20 k )=16 k . or 16 \%
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